(2x^2+3)(4x^3-3)=0

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Solution for (2x^2+3)(4x^3-3)=0 equation:


Simplifying
(2x2 + 3)(4x3 + -3) = 0

Reorder the terms:
(3 + 2x2)(4x3 + -3) = 0

Reorder the terms:
(3 + 2x2)(-3 + 4x3) = 0

Multiply (3 + 2x2) * (-3 + 4x3)
(3(-3 + 4x3) + 2x2 * (-3 + 4x3)) = 0
((-3 * 3 + 4x3 * 3) + 2x2 * (-3 + 4x3)) = 0
((-9 + 12x3) + 2x2 * (-3 + 4x3)) = 0
(-9 + 12x3 + (-3 * 2x2 + 4x3 * 2x2)) = 0
(-9 + 12x3 + (-6x2 + 8x5)) = 0

Reorder the terms:
(-9 + -6x2 + 12x3 + 8x5) = 0
(-9 + -6x2 + 12x3 + 8x5) = 0

Solving
-9 + -6x2 + 12x3 + 8x5 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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